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Question

When a polynomial p(x) is divided by x2, the remainder is 7. When p(x) is divided by x3, the remainder is 9. If r(x) is the remainder when p(x) is divided by (x2)(x3), then the value of r(1) is

A
0
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B
2
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C
4
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D
1
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Solution

The correct option is D 1
Given that p(2)=7 & p(3)=9
Let p(x)=(x2)(x3)g(x)+r(x)
Since the degree of the remainder is always less than the degree of divisor, we get
r(x)=Ax+B

2A+B=7 and 3A+B=9
A=2 and B=3
r(x)=2x+3
r(1)=1





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