The correct option is
A The collector voltage becomes less positive.
Let IB and Ic be the base current and collector current respectively.
Using Kirchhoff's loop law in loop (1) we get,
−VBB+IBRs+VBE=0⟹IB=VBB−VBERs .......... (1)
Thus, if VBB increases then base current (IB) increases
Also collector current, Ic=βIB, where β is the current gain.
Hence IC also increases due to increase in base current
Using Kirchhoff's loop law in loop (2) we get, −VCC+ICRL+VC=0⟹VC=VCC−ICRL ..........(2)
⟹ VC decreases due to increase in collector current (IC)
Hence, collector voltage (VC) becomes less positive when VBB is applied.
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