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Question

When a potential difference of 103 V is applied between A and B, a charge of 0.75 mC is stored in the system of capacitors. The value of C is (in μF)


A
3
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B
2.5
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C
2
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D
12
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Solution

The correct option is C 2
Given, VAB=103 V and QAB=0.75 mC
Effective capacitance CAB=1×(C+1)1+(C+1)
QAB=CABVAB
0.75×103=(C+1)1C+1+1×103
34×106=C+1C+2
C=2 μF

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