When a potential difference of 2V is applied across a resistor, you observed a current I. When the length of the resistor is doubled without changing the thickness, what is the current observed when 2V is applied across it.

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I/2

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Solution

The correct option is B
I/2

We know that R $α$ L

So when length is doubled, R is doubled.
So, for the same 2V potential difference, since V=IR,
R is doubled $⟹$ I is halved

So new current = I/2

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