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Resistivity

When a potent...

Question

When a potential difference of $3 V$ is applied between the two ends of a $60$ cm long metallic wire, current density in it is found to be $1 \times 10^{- 7} A m^{- 2}$ . Find conductivity of the material of the wire in SI system.

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Solution

Given: $V = 3 V$
Length $= 60$ cm $= 0.60$ m
$J = 1 \times 10^{- 7} A / m^{2}$
$E = \frac{V}{d}$
$= \frac{3}{0.60} = 5 V / m$
We know, $J = σ E$
$1 \times 10^{- 7} = σ \times 5$
$σ = 2 \times 10 - 8 (Ω m)^{- 1}$ .

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