When a pressure of 100 atmosphere is applied on a spherical ball of rubber, then its volume reduces to $0.01 %$ . The bulk modulus of the material of the rubber in $\frac{d y n e}{c m^{2}}$ is

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Solution

The correct option is C
1 atm = $10^{5} \frac{N}{m^{2}}$ $∴ 100 a t m = 10^{7} \frac{N}{m^{2}}$ and $Δ V = 0.01 % V$ $∴ \frac{Δ V}{V} = 0.0001$
$K = \frac{P}{\frac{Δ V}{V}} = \frac{10^{7}}{0.0001} = 1 \times 10^{11} \frac{N}{m^{2}} = 1 \times 10^{12} \frac{D y n e}{c m^{2}} .$

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When a pressure of 100 atmosphere is applied on a spherical ball of rubber, then its volume reduces to 0.01%. The bulk modulus of the material of the rubber in dynecm2 is

The correct option is C 1 atm = 105Nm2 ∴100atm=107Nm2 and ΔV=0.01%V ∴ΔVV=0.0001 K=PΔVV=1070.0001=1×1011Nm2=1×1012Dynecm2.

When a pressure of 100 atmosphere is applied on a spherical ball of rubber, then its volume reduces to $0.01 %$ . The bulk modulus of the material of the rubber in $\frac{d y n e}{c m^{2}}$ is

The correct option is C
1 atm = $10^{5} \frac{N}{m^{2}}$ $∴ 100 a t m = 10^{7} \frac{N}{m^{2}}$ and $Δ V = 0.01 % V$ $∴ \frac{Δ V}{V} = 0.0001$
$K = \frac{P}{\frac{Δ V}{V}} = \frac{10^{7}}{0.0001} = 1 \times 10^{11} \frac{N}{m^{2}} = 1 \times 10^{12} \frac{D y n e}{c m^{2}} .$