Question

When a pure strain of tall plants (TT) with round seeds (RR) is crossed with a pure strain of short plants (tt) with wrinkled seeds (rr), an $F_1$ generation is produced. The alleles for short and wrinkled are recessive to those for tall and round, respectively. When these $F_1$ plants self-pollinate, what proportion of the $F_2$ generation is short with wrinkled seeds?

• A. 0
• B. $\frac{1}{16}$
• C. $\frac{1}{2}$
• D. $\frac{9}{16}$

Answer 1

The correct option is B $\frac{1}{16}$

Dihybrid cross is the one which involves two pairs of contrasting traits. Mendel found that a cross between tall round and wrinkled short seeds produced only round and tall seeds in F1 generation but in F2 generation the combination observed are

Round tall 9 parental combinations

Round short 3 parental combinations

Wrinkled tall 3 parental combination

Wrinkled short 1 parental combination

So, the correct option is '1/16'