When a ray is refracted from one medium to another,the wavelength changes from $60000$ Angstorm to $40000$ Angstorm the critical angle for the interface will be

{cos}^{- 1} (\frac{2}{3})

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{sin}^{- 1} (\frac{2}{\sqrt{3}})

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{sin}^{- 1} (\frac{2}{3})

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{cos}^{- 1} (\frac{2}{\sqrt{3}})

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Solution

The correct option is D ${sin}^{- 1} (\frac{2}{3})$
Refractive index $= sin (\frac{60000}{21000})$ it can also be written as;
${sin}^{- 1} (\frac{40000}{60000})$
${sin}^{- 1} (\frac{2}{3})$
$∴$ C is correct option.

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When a ray is refracted from one medium to another, the wavelength changes from $600 \circ A t o 400 \circ A$ . The critical angle for the interface will be

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; evaluate:

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Q. Prove that:
(i)

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(ii)

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The critical angle for a light ray travelling from denser to rarer medium is defined as the angle of incidence at which the light refracts at $90^{\circ}$ (angle of refraction).

If a ray of light travels from water (μ_w) to air (μ_a).

Find the critical angle?

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When a ray is refracted from one medium to another,the wavelength changes from 60000 Angstorm to 40000 Angstorm the critical angle for the interface will be

The correct option is D sin−1(23)Refractive index=sin(6000021000) it can also be written as;sin−1(4000060000)sin−1(23)∴ C is correct option.

When a ray is refracted from one medium to another,the wavelength changes from $60000$ Angstorm to $40000$ Angstorm the critical angle for the interface will be

The correct option is D ${sin}^{- 1} (\frac{2}{3})$
Refractive index $= sin (\frac{60000}{21000})$ it can also be written as;
${sin}^{- 1} (\frac{40000}{60000})$
${sin}^{- 1} (\frac{2}{3})$
$∴$ C is correct option.