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Question

When a resistor of 11Ω is connected in series with a electric cell. The current following in it is 0.5A. Instead when a resistor of 5Ω is connected to the same electric cell in series, the current increases by 0.4A. The internal resistance of the cell is

A
1.5Ω
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B
2Ω
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C
2.5Ω
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D
3.5Ω
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Solution

The correct option is B 2.5Ω
Here, i=ER+r
0.5=E11+rE=5.5+0.5r
0.9=E5+r or, E=4.5+0.9r
On solving we get r=2.5Ω

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