When a ring is rolling, $V_{1}, V_{2}, V_{3}$ and $V_{4}$ are velocities of top most point, lowest point, end point of horizontal diameter and centre of ring respectively. The decreasing order of these velocities is:

V_{2}, V_{1}, V_{4}, V_{3}

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V_{2}, V_{1}, V_{3}, V_{4}

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V_{1}, V_{2}, V_{3}, V_{4}

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V_{1}, V_{3}, V_{4}, V_{2}

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Solution

The correct option is D $V_{1}, V_{3}, V_{4}, V_{2}$
Let velocity of centre
$= V_{0}$
$V_{4} = V_{0}$
$V_{1} = 2 V_{0}$
$V_{2} = 0$
$V_{3} = \sqrt{2} V_{0}$
$∴ V_{1} > V_{3} > V_{4} > V_{2}$

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When a ring is rolling, V1,V2,V3 and V4 are velocities of top most point, lowest point, end point of horizontal diameter and centre of ring respectively. The decreasing order of these velocities is:

The correct option is D V1,V3,V4,V2Let velocity of centre=V0V4=V0V1=2V0V2=0V3=√2V0∴V1>V3>V4>V2

When a ring is rolling, $V_{1}, V_{2}, V_{3}$ and $V_{4}$ are velocities of top most point, lowest point, end point of horizontal diameter and centre of ring respectively. The decreasing order of these velocities is:

The correct option is D $V_{1}, V_{3}, V_{4}, V_{2}$
Let velocity of centre
$= V_{0}$
$V_{4} = V_{0}$
$V_{1} = 2 V_{0}$
$V_{2} = 0$
$V_{3} = \sqrt{2} V_{0}$
$∴ V_{1} > V_{3} > V_{4} > V_{2}$