When a rod is heated from 25∘ to 75∘, it expands by 1 mm. When a rod of same material but with 4 times the length is heated from 25∘ to 50∘. The increase in length is
A
1mm
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B
1.5 mm
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C
1.6 mm
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D
2 mm
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Solution
The correct option is D 2 mm Δl=l0αΔTImm=l0α50;Δ1=4l0α.25⇒Δl=4×lmm50×25=2mm