Question

When a rubber ball is taken to bottom of lake, its volume reduces by 0.1% then depth of lake (Bulk modulus rubber is $6\times {10}^{8}N/m^2$)

• A. 60 m
• B. 120 m
• C. 150 m
• D. 30 m

Answer 1

Answer: (A)

60 m

Given decrease in volume $(\frac{\Delta V}{v}\times 100)=-0.1\%$

Bulk modulus of rubber $\left(\beta \right)=6\times {10}^{8}N/m^2$

depth of lake Let $d$

we Know Putting value $6\times {10}^8=\frac{+{10}^3\times 10\times d}{+0.1\times {10}^{-2}}\{\begin{array}{c}{P}_{\text{water}}={10}^{3}Kg/m^3\\ g=10m/s^2\end{array}$ $d=60m$