When a sample of gas expands from $4.0 L$ to $12.0 L$ against a constant pressure of $0.3$ atm, the work done is:

243.19 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 243.18 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

234.19 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 234.19 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $- 243.18 J$
Work done $W = - P Δ V$
$W = - 0.3 \times (12 - 4)$
$W = - 2.4 a t m L$
$W = - 2.4 \times 101.325 J$
$W = - 243.18 J$

Suggest Corrections

Similar questions

100

250

2

25^{o} C

0.01

4.0 L

1.0 L

4.0

△ U

A gas expands by $0.5$ L against a constant pressure of $1$ atm. The work done in calories is:

Join BYJU'S Learning Program