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Question

When a screw gauge with a least count of 0.01 mm is used to measure the diameter of a wire, the reading on the sleeve is found to be 1 mm and the reading on the thimble is found to be 27 divisions.
(i) What is the diameter of the wire in cm?
(ii) If the zero error is +0.005 cm, what is the correct diameter?

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Solution

Reading = Linear scale reading + (coinciding circular scale × least count)
=0.1+(27×0.001)
=0.127 cm

True diameter = observed diameter zero error
=0.1270.005=0.122cm

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