When a shot-put champion releases a 5.0 kg shot, it is at 1.5 m above the ground and travelling at 10 $\frac{m}{s}$ . It reaches a maximum height of 5 m above the ground. What are the total mechanical energy, kinetic energy and potential energy of the shot at its maximum height?

325 J, 75 J, 250 J

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450 J, 125 J, 325 J

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300 J, 100 J, 200 J

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350 J, 125 J, 225 J

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Solution

The correct option is A
325 J, 75 J, 250 J

Substituting the values of mass, height and velocity of the shot in the formula:
Total energy = Potential energy + Kinetic energy = m $\times$ g $\times$ h + $\frac{1}{2}$ m $v^{2}$ = 325 J
The total mechanical energy will remain the same throught the flight.
Now, Potential energy = mgh = (5 $\times$ 10 $\times$ 5) = 250 J and Kinetic energy = 325 J - 250 J = 75 J

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When a shot-put champion releases a 5.0 kg shot, it is at 1.5 m above the ground and travelling at 10 ms. It reaches a maximum height of 5 m above the ground. What are the total mechanical energy, kinetic energy and potential energy of the shot at its maximum height?

When a shot-put champion releases a 5.0 kg shot, it is at 1.5 m above the ground and travelling at 10 $\frac{m}{s}$ . It reaches a maximum height of 5 m above the ground. What are the total mechanical energy, kinetic energy and potential energy of the shot at its maximum height?