Question

When a slab of dielectric material is introduced between the parallel plates of capacitor which remains connected to a battery, then charge on plates relative to earlier charge

• A. is less
• B. is more
• C. is same
• D. May be less or more depending on the nature of the material introduced
  

Answer 1

The correct option is B is more

Charge on capacitor $Q=CV$, where $V$= potential difference .

• After inserting dielectric of dielectric constant $k$ , capacitance becomes $kC$ where $k>1$ .
• Thus, when dielectric is inserted, capacitance will increase, and voltage will remain same as the same cell is still connected .
• Hence, charge will increase.

Hence, correct option is (C).