When a small lamp is held 1.5m above the surface of the water in a tank, its image formed by reflection at the surface appears to coincide with the image of the bottom of the tank. (μ of water =1.33)
The depth of the tank is
It is given that the lamp is held 1.5m above surface of the water. Since it undergoes reflection, the depth of image also appears to be at 1.5m below the water surface.
Hence, apparent depth d=1.5m
Refractive index of water μ=1.33
We know the relation μ=Dd where D=real depth.
∴D=μ×d
⇒D=1.5×1.33=1.995m
Therefore the depth of the tank is almost equal to 2m.
Hence the correct answer is option (A).