Question

When a solution of conductance $1.342mho{m}^{-1}$ was placed in a conductivity cell with parallel electrodes, the resistance was found to be 170.5 ohm. The area of the electrodes is $1.86\times {10}^{-4}$ sq. meter. Calculate the distance between the two electrodes in meter.

• A. $4.25\times {10}^{-2}meters$
• B. $8.5\times {10}^{-2}meters$
• C. $3.25\times {10}^{-2}meters$
• D. $6.5\times {10}^{-2}meters$

Answer 1

The correct option is A $4.25\times {10}^{-2}meters$

As we know,

distance between two electrodes = $1.342\ast 170.5\ast 1.86\ast {10}^{-4}=4.25\times {10}^{-2}meters$