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Question

When a solution of Na2Cr2O7 is treated with amyl alcohol and acidified H2O2, the layer of amyl alcohol turns blue. What is the blue colouration?

A
Cr2+
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B
CrO5
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C
CrO4
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D
Cr2++CrO5
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Solution

The correct option is A CrO5
When a solution of Na2Cr2O7 is treated with amyl alcohol, then, there is formation of the chromate ion.
Na2Cr2O7+2OH2NaCrO24+H2O

On reacting with acidified H2O2 converts to CrO5 to give the blue coloration,
Na2CrO4+2H2O2+2H+CrO5+3H2O+2Na+

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