Question

When a sound wave of wavelength $\lambda$ is propagating in a medium the maximum velocity of the particle is equal to wave velocity. The amplitude of the wave is

• A. $\lambda$
• B. $\frac{\lambda }{2}$
• C. $\frac{\lambda }{2\pi }$
• D. $\frac{\lambda }{4\pi }$

Answer 1

The correct option is C $\frac{\lambda }{2\pi }$

wave velocity of particle $v=\frac{w}{K}$
maximum particle velocity $v_2=Aw$
given $Aw=\frac{w}{K}\Rightarrow A=\frac{1}{K}=\frac{1}{\frac{2\pi }{\lambda }}=\frac{\lambda }{2\pi }$