When a sound wave of wavelength λ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is:
A
λ
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B
λ2
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C
λ2π
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D
λ4π
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Solution
The correct option is Cλ2π For all waves consisting of simple harmonic oscillation, the maximum velocity of particle is given as, ⇒(vP)max=Aω A→amplitude of wave
Also the velocity of wave is given by, v=ωk=ω2πλ (∵k=2πλ) ⇒v=λω2π
Given, (vP)max=v ⇒Aω=λω2π ⇒A=λ2π