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Speed of Sound

When a source...

Question

When a source moves away from a stationary observer, the frequency is 6/7 times the original frequency. Given: speed of sound = 330 m/s. The speed of the source is

A

40 m/s

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B

55 m/s

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C

330 m/s

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D

165 m/s

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Solution

The correct option is B 55 m/s
$v^{'} = \frac{v}{v + v_{s}} v o r \frac{6}{7} v = \frac{330}{330 + v_{s}} v o r 6 \times 330 + 6 v_{s} = 7 \times 330 o r 6 v_{s} = 330 o r v_{s} = 55 m / s$

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