When a space ship is at a distance of two earth radius from the centre of the earth the gravitational acceleration is:

19.6

{m s}^{- 2}

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9.8

{m s}^{- 2}

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4.9

{m / s}^{- 2}

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2.45

{m s}^{- 2}

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Solution

The correct option is D 2.45 ${m s}^{- 2}$
It is known that, $g = (\frac{G M}{R^{2}})$

$g = 9.8 \frac{m}{s e c^{2}}$

When the distance from center of the earth = $2 R$

So, $g = (\frac{G M}{2 R^{2}})$

$= (\frac{G M}{4 R^{2}})$

$= \frac{9.8}{4}$

$= 2.45 \frac{m}{s e c^{2}}$

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When a space ship is at a distance of two earth radius from the centre of the earth the gravitational acceleration is:

The correct option is D 2.45ms−2It is known that, g=(GMR2)g=9.8msec2When the distance from center of the earth = 2RSo, g=(GM2R2)=(GM4R2)=9.84=2.45msec2

The correct option is D 2.45 ${m s}^{- 2}$
It is known that, $g = (\frac{G M}{R^{2}})$

$g = 9.8 \frac{m}{s e c^{2}}$

When the distance from center of the earth = $2 R$

So, $g = (\frac{G M}{2 R^{2}})$

$= (\frac{G M}{4 R^{2}})$

$= \frac{9.8}{4}$

$= 2.45 \frac{m}{s e c^{2}}$