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Springs in Parallel and Series

When a Spring...

Question

When a Spring of constant K is cut into 2 equal parts then new spring constant of both the parts would be:

A

K

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B

2K

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C

4K

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D

None of these

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Solution

The correct option is B 2K
$F = K L K = \frac{F}{L} K \propto \frac{1}{L}$
So when it is cut into two equal parts its length decreases to half & simultaneously spring constant increases to $2 K$

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