When a stretched wire and a tuning fork are sounded together, 5 beats per second are produced, when length of wire is 95cm or 100cm, frequency of the fork is
A
90Hz
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B
100Hz
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C
105Hz
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D
195Hz
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Solution
The correct option is A195Hz Let the frequency of tuning fork be m. Suppose l1=95cm has frequency n1 and l2=100cm has frequency n2(<n1) Now, n1−n=5.....(i) n−n2=5.....(ii) Adding, we get n1−n2=10.....(iii) Also, n1n2=l2l1=10095 n1=10095n2 From eqn. (iii), 10095n2−n2=10,n2=190 From eqn. (ii), n=n2+5=190+5=195Hz.