wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

When a string is divided into three segments of lengths l1,l2,andl3, the fundamental frequencies of these three segments are v1,v2andv3, respectively. The original fundamental frequency (v) of the string is

A
v=v1+v2+v3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
v=v1+v2+v3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1v=1v1+1v2+1v3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1v=1v1+1v2+1v3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1v=1v1+1v2+1v3
V=12lTmv1l1=v2l2=v3l3=kfromeq.(1)l1=kv1,l2=kv2,l3=kv3originallengthl=kvHere,l=l1+l2+l3kv=k1v1+k2v2+k3v31v=1v1+1v2+1v3
Hence, Option C is correct .

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Normal Modes on a String
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon