When a substance having mass 3 kg receives 600 cal of heat, its temperature increases by $10^{0}$ C. What is the specific heat of the substance?

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Solution

We know that $Q = m s d t$
Q is 600 caloriee
M is 3 kg
dt is 10 degree
600cal=3×10×s×kgcelsius
s=20. Cal/kg celsius

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When a substance having mass 3 kg receives 600 cal of heat, its temperature increases by 100C. What is the specific heat of the substance?

We know that Q=msdtQ is 600 calorieeM is 3 kgdt is 10 degree600cal=3×10×s×kgcelsiuss=20. Cal/kg celsius

When a substance having mass 3 kg receives 600 cal of heat, its temperature increases by $10^{0}$ C. What is the specific heat of the substance?

We know that $Q = m s d t$
Q is 600 caloriee
M is 3 kg
dt is 10 degree
600cal=3×10×s×kgcelsius
s=20. Cal/kg celsius