When a system is taken from state a to state b along the path a−c−b,60J of heat flows into the system and 30J of work is done by the system. Along the path a−d−b, if the work done by the system is 10J, heat flow into the system is
A
6J
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B
12J
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C
18J
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D
40J
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Solution
The correct option is D40J Qacb=ΔUacb+Wacb Qbda=ΔUbda+Wbda Qacb+Qbda=(ΔUacb+ΔUbda)+Wacb+Wbda ΔUacb+ΔUbda=0 ⇒60+Qbda=30−10 Qbda=−40J Qadb=40J