When a system is taken from state i to state f along the path iaf, it is found that Q=50cal and W=20cal. Along the path ibf, Q=36cal, W along the path ′ibf′ is :
A
6cal
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B
16cal
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C
66cal
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D
14cal
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Solution
The correct option is A6cal By first law of thermodynamics : Q=ΔU+W
In path iaf: 50=ΔU+20∴ΔU=30 As this change in internal energy is between i & f and does not depend on path.