Question

When a tube-light rated 220v, 60w is connected across a potential of 220v for 22 seconds then find the charge flowing through it.

• A. 4 C
• B. 22 C
• C. 6 C
• D. 20 C

Answer 1

The correct option is C

6 C

$R=\frac{V^2}{P}=$
Now using ohm's law
V = IR
$I=\frac{V}{R}[\frac{v}{v^2}\times P]$
$Now,I=\frac{q}{t}q=It\Rightarrow \frac{v}{v^2}\times P\times t\Rightarrow \frac{60\times 22}{220}=6C$