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Byju's Answer

Standard XII

Physics

Beat Frequency

When a tuning...

Question

When a tuning fork of frequency 341 is sounded with another tuning fork, six

beats per second are heard. When the second tuning fork is loaded with wax

and sounded with the first tuning fork, the number of beats is two per

second. The natural frequency of the second tuning fork is

[MP PET 1989]

334

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339

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343

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347

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Solution

The correct option is D
347

$n_{A}$ = Known frequency = 341 Hz, $n_{B}$ = ?

x = 6 bps , which is decreasing $(i . e . x ↓)$ after

loading ( from 6 to 1 bps )

Unknown tuning fork is loaded so $n_{B} ↓$

Hence $n_{A} - n_{B} ↓= x ↓$ ....(i) -----> Wrong

$n_{B} ↓ - n_{A} = x ↓$ .....(ii) -----> Correct

$\Rightarrow n_{B} = n_{A} + x = 341 + 6 = 347 H z .$

Suggest Corrections

Similar questions

Q. When a tuning fork of frequency 341 Hz is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first fork, the number of beats is two per second. The natural frequency (in

Hz

)of the second tuning fork is

Q. A tuning fork

A

of unknown frequency produces

4

beats per second when sounded with another tuning fork

B

of frequency

254 Hz

. When tuning fork

A

is loaded with wax, it still gives

4

beats per second with tuning fork

B

. The initial unknown frequency of tuning fork

A

Q. A tuning fork

A

of unknown frequency produces

4

beats per second when sounded with another tuning fork

B

of frequency

254 Hz

. When tuning fork

A

is loaded with wax, it still gives

4

beats per second with tuning fork

A

. The initial unknown frequency of tuning fork

A

Q. When two tuning forks, fork

A

and fork

B

are sounded together,

4

beats per second are heard. When the tuning fork

B

is loaded with wax then

6

beats per second are heard. If the frequency of fork

A

200 Hz

then what was the original frequency of fork

B

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When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork is [MP PET 1989]

The correct option is D 347 nA = Known frequency = 341 Hz, nB = ? x = 6 bps , which is decreasing (i.e.x↓) after loading ( from 6 to 1 bps ) Unknown tuning fork is loaded so nB↓ Hence nA−nB↓=x↓ ....(i) -----> Wrong nB↓−nA=x↓ .....(ii) -----> Correct ⇒nB=nA+x=341+6=347Hz.

When a tuning fork of frequency 341 is sounded with another tuning fork, six

beats per second are heard. When the second tuning fork is loaded with wax

and sounded with the first tuning fork, the number of beats is two per

second. The natural frequency of the second tuning fork is

[MP PET 1989]