CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

When a tuning fork of frequency 341 is sounded with another tuning fork, six 

beats per second are heard. When the second tuning fork is loaded with wax 

and sounded with the first tuning fork, the number of beats is two per 

second. The natural frequency of the second tuning fork is

[MP PET 1989]



A

334

loader
B

339

loader
C

343

loader
D

347

loader

Solution

The correct option is D

347


nA = Known frequency = 341 Hz, nB = ? 

x = 6 bps , which is decreasing (i.e.x) after 

loading ( from 6 to 1 bps ) 

Unknown tuning fork is loaded so nB 

Hence  nAnB=x      ....(i)    -----> Wrong 

           nBnA=x      .....(ii)   -----> Correct 

nB=nA+x=341+6=347Hz. 


Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image