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Question

When a U238 nucleus originally at rest, decay by emitting an alpha particle having a speed 1.5×107 m1. Then calculate the kinetic energy of the residual nucleus.

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Solution

Mass of α particle, mα=4u

Mass of nucleus after fission, mn=234u

From conservation of momentum

Final momentum = initial momentum

mαvα+mnvn=0

4×1.5×107+234vn=0

vn=2.56×105ms1

Hence, velocity of nucleus is 2.56×105ms1


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