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Question

When a U238 nucleus originally at rest decays by emitting an alpha particle having velocity u, the recoil velocity of the residual nucleus is

A
4u238
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B
u238
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C
4u234
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D
u234
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Solution

The correct option is C 4u234

The momentum of the system remains the same before and after decay. This is in accordance with the principle of conservation of momentum.

Now, 4u+234v=238×0
or 234v=4u or v=4u234
So, (c) is the right choice.


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