When a voltage Vs=200√2sin(ωt+15∘)V is applied to an ac circuit, the current in the circuit is found to be i=2sin[ωt+(π/4)]A. If the average power consumed in the circuit is x√6W. Find x
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Solution
Using above attached concept Vmax = 200√2V Imax = 2 A ϕ = 45 - 15 = 30 Pavg = 12VmaxImaxCosϕ=12×200√2×2×Cos30=100√6 so x= 100