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Question

When a wheat variety of red kernels (homozygous for two nonallelic and independent dominant genes) is crossed with white kernelled wheat (homozygous for two recessive nonallelic independent genes), the phenotypic ratio in F2 generation would be

A
9 : 7
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B
1 : 10 : 4 : 1
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C
1 : 4 : 6 : 4 : 1
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D
1 : 2 : 4 : 2 : 4 : 2 : 1
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Solution

The correct option is C 1 : 4 : 6 : 4 : 1

In a cross, two wheat plants are used, in which one wheat plant shows red kernels and another wheat plant shows white kernels.

Kernel colour of wheat is determined by two pairs of genes AA and BB. Genes A and B determine the red colour of kernel and are dominant over their recessive alleles. Each gene pair shows mendelian segregation.

When a cross is made between the two plants, the grains of F1 were uniformly red but intermediate between red and white of parental generations. When F1 plants were selfed, in the F2 generations progeny with five different types of phenotypes are obtained and the ratio is described as 1:4:6:4:1. It is due to the control of character by more than one gene. It is called Polygenic inheritance.

So, the correct option is ‘1:4:6:4:1’.

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