When AABB and aabb are crossed, in F $_{2}$ generation the ratio of AaBb will be

1/16

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2/16

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8/16

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4/16

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Solution

The correct option is D 4/16
AABB x aabb -----> AaBb (F $_{1}$ )
Selfing of F $_{1}$ : AaBb X AaBb
Gametes: AB, Ab, aB, ab
AABB,
AABb,
AaBB
, AaBb
AABb,
AAbb,
AaBb,
Aabb
AaBB,
AaBb,
aaBB,
aaBb
AaBb,
Aabb,
aaBb,
aabb
From the punnett square it is evident that, there are occurences of AaBb 4 times out of 16 progenies produced.
Thus, the ratio is 4:16

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