When acetaldehyde reacts with semicarbazide, the product formed is :

C H_{3} C H = N N H - C O - N H_{2}

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C H_{3} C H = N C O N H N H_{2}

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C H_{3} C H = N H N H_{2}

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C H_{3} - C O - N H - C O N H_{2}

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Solution

The correct option is A $C H_{3} C H = N N H - C O - N H_{2}$
Acetaldehyde reacts with semicarbazide, product will be $C H_{3} C H = N N H - C O - N H_{2}$ .

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