Question

When acidified $K_{2}C{r}_2{O}_7$ solution is added to $S{n}^{2+}$ changes to:

• A. $S{n}^{4+}$
• B. $S{n}^{+}$
• C. $S{n}^{3+}$
• D. $Sn$

Answer 1

The correct option is A $S{n}^{4+}$

When acidified $K_{2}C{r}_2{O}_7$ solution is added to $S{n}^{2+}$, it oxidises $S{n}^{2+}$ to $S{n}^{4+}$.

$C{r}_2{O}_7^{2-}+14H^{+}+3S{n}^{2+}\to 2C{r}^{3+}+3S{n}^{4+}+7H_{2}O$

$Sn$ belongs to the carbon family which generally shows $+2$ and $+4$ oxidation states. So, on oxidation, $Sn$ cannot show $+3$ oxidation state.

So, option $\left(C\right)$ is the correct answer.