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Variable Oxidation States

When AgNO 3 i...

Question

When $A g N O_{3}$ is treated with hypo solution, a white ppt of A is formed. This gets dissolved when excess of hypo solution is added due to the formation of compound B. Precipitate A on boiling with water turns black due to the formation of C. Find the incorrect option:

White precipitate is due to

N a_{3} [A g (S_{2} O_{3})_{2}]

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Black precipitate is due to

A g_{2} S

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Along with

C

H_{2} S O_{4}

is also formed

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Average oxidation state of

S

in hypo solution is

+ 2

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Solution

The correct option is A White precipitate is due to $N a_{3} [A g (S_{2} O_{3})_{2}]$
$2 A g N O_{3} + N a_{2} S_{2} O_{3} \to A g_{2} S_{2} O_{3} w h i t e p p t (A) ↓ + 2 N a N O_{3}$
$A g_{2} S_{2} O_{3} + 3 N a_{2} S_{2} O_{3} \to 2 N a_{3} [A g (S_{2} O_{3})_{2}] B$
$A g_{2} S_{2} O_{3} + H_{2} O b o i l - - \to A g_{2} S C ↓ + S O_{4}^{2 -} + 2 H^{+}$
So,
a) White precipitate is due to $A g_{2} S_{2} O_{3}$
b) Black precipitate is due to $A g_{2} S$
c) Along with $C$ , $H_{2} S O_{4}$ is also formed
d) Average oxidation state of $S$ in $N a_{2} S_{2} O_{3}$ is $+ 2$ .

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When AgNO3 is treated with hypo solution, a white ppt of A is formed. This gets dissolved when excess of hypo solution is added due to the formation of compound B. Precipitate A on boiling with water turns black due to the formation of C. Find the incorrect option:

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