Question

When alcohol $\left(C_2{H}_{5}OH\right)$ and acetic acid are mixed together in equimolar ratio at ${27}^{\circ }C,33$ % is converted into ester. Then the $K_c$ for the equilibrium is:
$C_2{H}_{5}OH\left(l\right)+C{H}_{2}COOH\left(l\right)\rightleftharpoons C{H}_{3}COO{C}_2{H}_5\left(l\right)+H_{2}O\left(l\right)$

• A. $4$
• B. $1/4$
• C. $9$
• D. $1/9$

Answer 1

The correct option is B $1/4$

$C_2{H}_{5}OH\left(l\right)+C{H}_{2}COOH\left(l\right)\rightleftharpoons C{H}_{3}COO{C}_2{H}_5\left(l\right)+H_{2}O\left(l\right)$

$1-0.33$

$1-0.33$

$0.33$

$0.33$

$K_c=\frac{0.33\times 0.33}{0.67\times 0.67}=\frac{1}{4}$