Question

when alpha d glucose is dissolved in water it undergoes partial conversion to beta d glucose to exhibit muta rotation.this conversion stops when 63.6% of glucose is in beta form.assuming equilibrium to be attained find kc for the reaction.

Answer 1

$$\begin{gathered} \alpha -Glu\cos e\leftrightarrow \beta -Glu\cos e \\ Initial:10 \\ Ateqm1-\alpha \alpha \\ Since\alpha =0.636 \\ 1-0.6360.636 \\ {K}_C=\frac{[\beta -Glucose]}{[\alpha -Glucose]} \\ =\frac{0.636}{0.364}=1.747 \end{gathered}$$