When an alkaline earth metal M reacts with oxygen the formula of the compound produced will be :

M_{2} O

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M O

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M_{2} O_{3}

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M O_{2}

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M_{3} O_{4}

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Solution

The correct option is B $M O$
As the electrovalency of alkaline earth metal is +2, whereas that of Oxygen is $- 2$ , hence, the formula of them will be $M O$ .

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