When an aqueous solution of sodium sulphate is electrolysed, on cathode we get:

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H₂

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SO₂

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SO₃

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Solution

The correct option is B
H₂

During electrolysis of aqueous sodium sulphate, water gets reduced at the cathode liberating hydrogen gas and oxygen gets liberated at the anode due to oxidation.
At cathode:
$2 H_{2} O + 2 e^{-} \to H_{2} + 2 O H^{-}$ At anode:
$2 H_{2} O \to O_{2} + 4 H^{+} + 4 e^{-}$

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