When an electric cell drives current through load resistance, its back emf,

Supports the original emf

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Opposes the original emf

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Supports if internal resistance is low

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Opposes if load resistance is large

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Solution

The correct option is B Opposes the original emf
A figure is shown above. According to given circuit idea, the current will flow from $- v e$ pole to $+ v e$ pole internally in the cell. Thereby generating back emf which is in opposition to the original emf.

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Similar questions

E

r

i

R

r

R

I

R = 9 Ω

E_{1} = 9 V

r_{1} = 1 Ω

E_{2} = 6 V

r_{2} = 3 Ω

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