Question

When an electric current is passed through acidulated water 112ml of hydrogen gas at STP collects at the cathode in 965 seconds. The current passed in ampere is:

• A. 1
• B. 0.5
• C. 0.1
• D. 2

Answer 1

Answer: (B)

0.5

Mole of hydrogen$=\frac{112}{22400}=\frac{1}{200}=0.005$

Charge required $=0.005\times 96500=482.5C$

$I\times t=482.5$

$I\times 965=482.5$

$\therefore$ $I=0.5A$

Hence, option B is correct.