When an electric currents passed through acidified water, 112mL of hydrogen gas at N.T.P. was collected the cathode in 965 seconds. The current passed, in ampere, is :
(JEE Main 2018)
A
0.1
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B
1.0
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C
0.5
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D
2.0
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Solution
The correct option is B1.0 Reaction at cathode: 2H++2e−→H2
We know, ω=zlt=EIt96500 <
no. of moles of H2=11222400 ∴ mass (w) of H2=11222400×2 ∴11222400×2=1×I×96596500 ⇒I=1A