Working voltage, V=230V
Power consumed, P=750W
(i) Let R be the resistance of the heating element
P=V2R or R=V2P
R=230×230750=70.53Ω
(ii) Current through the iron, I=PV=750230=3.26A
Therefore, the current that is passed through the iron is 3.26A.
Resistance of the heating element of the iron is 70.55Ω.