When an electron in hydrogen atom is excited, from its 4th to 5th stationary orbit, the change in angular momentum of electron is (Planck’s constant:h=6.6×10−34J−s)
A
4.16×10−34J−s
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B
3.32×10−34J−s
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C
1.05×10−34J−s
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D
2.08×10−34J−s
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Solution
The correct option is C1.05×10−34J−s Change in angular momentum ΔL=L2−L1=n2h2π−n1h2π⇒ΔL=h2π(n2−n1)=6.6×10−342×3.14(5−4)=1.05×10−34J−s