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Standard XII

Physics

Validating the Bohr's Model

When an elect...

Question

When an electron is excited to $n^{th}$ energy state in hydrogen, the possible number of spectral lines emitted are

n

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2 n

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\frac{n^{2} - n}{2}

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\frac{n^{2} + n}{2}

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Solution

The correct option is C $\frac{n^{2} - n}{2}$
The number of energy states below with level = $n - 1$
Total number of spectral lines= sum of the volume of each energy state.
Hence, Total spectral lines= $1 + 2 + 3 + . . . . . . . . . . . . n - 1$
$= \frac{(n - 1) n}{2} = \frac{n^{2} - n}{2}$

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When an electron is excited to n th energy state in hydrogen, the possible number of spectral lines emitted are

The correct option is C n2−n2The number of energy states below with level =n−1Total number of spectral lines= sum of the volume of each energy state.Hence, Total spectral lines=1+2+3+............n−1=(n−1)n2=n2−n2

When an electron is excited to $n^{th}$ energy state in hydrogen, the possible number of spectral lines emitted are

The correct option is C $\frac{n^{2} - n}{2}$
The number of energy states below with level = $n - 1$
Total number of spectral lines= sum of the volume of each energy state.
Hence, Total spectral lines= $1 + 2 + 3 + . . . . . . . . . . . . n - 1$
$= \frac{(n - 1) n}{2} = \frac{n^{2} - n}{2}$